Last updated at Aug. 16, 2021 by Teachoo

Transcript

Ex 3.3, 4 If A’ = [■8(−2&3@1&2)] and B = [■8(−1&0@1&2)] , then find (A + 2B)’ We need to find (A + 2B)’ Finding A A’ = [■8(−2&3@1&2)] A = (A’)’= [■8(−2&1@3&2)] Also, B = [■8(−1&0@1&2)] 2B = 2 [■8(−1&0@1&2)] = [■8(2(−1)&2(0)@2(1)&2(2))] = [■8(−2&0@2&4)] Now A + 2B = [■8(−2&1@3&2)] + [■8(−2&0@2&4)] = [■8(2+(−2)&1+0@3+2&2+4)] = [■8(0&1@5&6)] ∴ (A + 2B) = [■8(−4&1@5&6)] So, (A + 2B)’ = [■8(−4&5@1&6)]

Ex 3.3

Ex 3.3, 1

Ex 3.3, 2

Ex 3.3, 3

Ex 3.3, 4 Important You are here

Ex 3.3, 5 (i)

Ex 3.3, 5 (ii)

Ex 3.3, 6 (i)

Ex 3.3, 6 (ii) Important

Ex 3.3, 7 (i)

Ex 3.3, 7 (ii) Important

Ex 3.3, 8

Ex 3.3, 9

Ex 3.3, 10 (i) Important

Ex 3.3, 10 (ii)

Ex 3.3, 10 (iii) Important

Ex 3.3, 10 (iv)

Ex 3.3, 11 (MCQ) Important

Ex 3.3, 12 (MCQ)

Chapter 3 Class 12 Matrices (Term 1)

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.